Relate the image distance (v), object distance(u) , image height(h') and object height(h) for the formula of magnification (M).

M = $\frac{h}{h^{'}}$ = $\frac{v}{u}$

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M = $\frac{h^{'}}{h}$ = $\frac{- v}{u}$

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M = $\frac{h}{h^{'}}$ = $\frac{- v}{u}$

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M = $\frac{h}{h^{'}}$ = $\frac{u}{v}$

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Solution

The correct option is B
M = $\frac{h^{'}}{h}$ = $\frac{- v}{u}$

M = $\frac{h^{'}}{h}$ = $\frac{- v}{u}$ where h' is the image height, h is the object height, v is the image distance and u is the object distance. When the magnification becomes negative it means that the image formed is inverted.

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Similar questions

Relate the image distance ( $v$ ), object distance ( $u$ ) , image height ( $h^{^{'}}$ ) and object height ( $h$ ) to the formula of magnification $(M)$ for a mirror.

Q. Write down a formula for the magnification produced by a concave mirror.

(a) in terms of height of object and height of image
(b) in terms of object distance and image distance

Magnification = \frac{Image distance}{Object distance}

is the correct representation of the magnification formula.

Q. Magnification is also defined as the of image distance and object distance.

An object of 2 cm height is placed at a distance of 10 cm from a concave mirror of radius of curvature 30 cm. Find the image distance, height and magnification.

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Relate the image distance (v), object distance(u) , image height(h') and object height(h) for the formula of magnification (M).

The correct option is B M = h′h = −vu M = h′h = −vu where h' is the image height, h is the object height, v is the image distance and u is the object distance. When the magnification becomes negative it means that the image formed is inverted.

The correct option is B
M = $\frac{h^{'}}{h}$ = $\frac{- v}{u}$

M = $\frac{h^{'}}{h}$ = $\frac{- v}{u}$ where h' is the image height, h is the object height, v is the image distance and u is the object distance. When the magnification becomes negative it means that the image formed is inverted.