Relation between pressure (P) and average kinetic energy per unit volume of gas (E) is then?

P = \frac{2}{3}

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P = \frac{1}{3}

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P = \frac{1}{2}

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P = 3

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Solution

The correct option is A $P = \frac{2}{3}$ E.
$K i n e t i c e n e r g y = \frac{3 R T}{2} => K . E = \frac{3 P V}{2} S i n c e, P V = n R T, h e r e n = 1 m o l e T h e r e f o r e, P = \frac{2 E}{3 V}, (E = k i n e t i c e n e r g y) A s p e r q u e s t i o n, \frac{E}{V} = E (A s v o l u m e = 1) S o, P = \frac{2 E}{3}$

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Similar questions

The relation between the gas pressure P and average kinetic energy per unit volume E is

Internal energy and pressure for unit volume of gas are related by

A.)P=2/3E. B.)P=3/2E. C.)P=1/3E. D.)P=2E

P = \frac{2}{3}

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