Relation between pressure(P) and energy density (E) of an ideal gas is:

P = 2 / 3 E

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P = 3 / 2 E

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P = 3 / 5 E

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P - E

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $P = 2 / 3 E$
For an ideal gas : $P V = R T$
And the internal energy of an ideal gas:
$E_{i n} = \frac{3}{2} R T$
$E_{i n} = \frac{3}{2} P V$
$\frac{E_{i n}}{V} = \frac{3}{2} P$
Energy density $(E) = \frac{3}{2} P$
$P = 2 / 3 E$

Suggest Corrections

Similar questions

(P)

(E)

Internal energy and pressure for unit volume of gas are related by

A.)P=2/3E. B.)P=3/2E. C.)P=1/3E. D.)P=2E

P = \frac{2 E}{3 V}

E

Join BYJU'S Learning Program