Question

Relation between wavelength of photon and electron of same energy is

• A. ${\lambda }_{ph}>{\lambda }_e$
• B. ${\lambda }_{ph}<{\lambda }_e$
• C. ${\lambda }_{ph}={\lambda }_e$
• D. $\frac{{\lambda }_e}{{\lambda }_{ph}}=constant$

Answer 1

Answer: (A)

${\lambda }_{ph}>{\lambda }_e$

For the same energy, the momentum of electron is more than that of photon $\Rightarrow p_e>p_{ph}$
${\lambda }_e=\frac{h}{p_e}and{\lambda }_{ph}=\frac{h}{p_{ph}}\Rightarrow {\lambda }_{ph}>{\lambda }_e$