Represent 3x=2y−2 in standard form ax+by+c=0
and find the values of a,b and c.
Which options are correct?
(3,-2, 2)
(2,1,4)
The given equation is
3x=2y−2.
After rearranging the equation, we get:
⇒3x−2y+2=0
Thus, the values of a,b and c are
3,−2 and 2 respectively.