Resistances of 2 - and 3 - are connected in series- If the P-D across the 2 - resistor is 3 V- the P-D across 3 - is -

The correct option is A 4.5 V V_2 = 3V R_eq=5 Ω I =V_22 = 32 = 1.5 A V_3 = 1.5 × 3 = 4.5 V ...

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Standard XII

Physics

Mixed Combination of Cells

Resistances o...

Question

Resistances of $2 Ω$ and $3 Ω$ are connected in series. If the P.D across the $2 Ω$ resistor is 3 V, the P.D across $3 Ω$ is :

4.5 V

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9 V

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3 V

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2 V

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Solution

The correct option is A 4.5 V
$V_{2} = 3 V$
$R_{e q} = 5 Ω$
$I = \frac{V_{2}}{2} = \frac{3}{2} = 1.5 A$
$V_{3} = 1.5 \times 3 = 4.5 V$

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Resistances of 2Ω and 3Ω are connected in series. If the P.D across the 2Ω resistor is 3 V, the P.D across 3Ω is :

The correct option is A 4.5 VV2=3VReq=5ΩI=V22=32=1.5AV3=1.5×3=4.5V

Resistances of $2 Ω$ and $3 Ω$ are connected in series. If the P.D across the $2 Ω$ resistor is 3 V, the P.D across $3 Ω$ is :

The correct option is A 4.5 V
$V_{2} = 3 V$
$R_{e q} = 5 Ω$
$I = \frac{V_{2}}{2} = \frac{3}{2} = 1.5 A$
$V_{3} = 1.5 \times 3 = 4.5 V$