Question

Resistances of 6 ohm each are connected in the manner shown in adjoining figure. With the current ampere as shown in figure, the potential difference $V_P-V_Q$ is

• A. 3.6 V
• B. 3.0 v
• C. 6.0 v
• D. 7.2 v

Answer 1

The correct option is B

3.0 v

the compressed circuit will look like-

$R_{eqv}=2\Omega +4\Omega =6\Omega ,I=0.5A$
We know, $V=IR=0.5A\times 6\Omega =3V$