Resolve $2 b^{2} - 5 b - 3$ in to factors.

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Solution

Given, $2 b^{2} - 5 b - 3$

$= 2 b^{2} - 6 b + b - 3$

$= 2 b (b - 3) + 1 (b - 3)$

$= (b - 3) (2 b + 1)$

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