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Question

Resolve each of the following quadratic trinomial into factor:
(2a − b)2 + 2(2a − b) − 8

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Solution

Assuming x=2a-b, we have: (2a-b)2+2(2a-b)-8=x2+2x-8The given expression becomes x2+2x-8. (Coefficient of x2=1 and that of x=2 ; constant term=-8)Now, we will split the coefficient of x into two parts such that their sum is 2 and their product equals the product of the coefficient of x2 and the constant term, i.e., 1×(-8)=-8.Clearly,(-2)+4=2 and(-2)×4=-8Replacing the middle term 2x by -2x+4x, we get:x2+2x-8=x2-2x+4x-8 =(x2-2x)+(4x-8) =x(x-2)+4(x-2) =(x+4)(x-2)Relacing x by 2a-b, we get:(x+4)(x-2)=(2a-b+4)(2a-b-2)

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