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Question

Resolve the following quadratic trinomial into factors :
14x2+11xy15y2

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Solution

Given : 14x2+11xy15y2
On splitting the middle term, we get
14x2+21xy10xy15y2
=7x(2x+3y)5y(2x+3y)
=(2x+3y)(7x5y)

Hence, 14x2+11xy15y2=(2x+3y)(7x5y).

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