Ria booked a cab at 10 pm. Due to peak hours the cab charged 2.5 times the normal fare. If the normal fare is ₹293.50. Find her total fare.

₹667.50

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₹867.43

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₹533.25

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₹733.75

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Solution

The correct option is D
₹733.75

As the cab charges 2.5 times the normal fare, the original fare gets multiplied by the extra charges.

So, $2.5 \times 293.50 = \frac{25}{10} \times \frac{2935}{10} = \frac{73375}{100} = 733.75$ .

Now Ria has to pay ₹733.75 as the total fare.

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Ria booked a cab at 10 pm. Due to peak hours the cab charged 2.5 times the normal fare. If the normal fare is ₹293.50. Find her total fare.

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Q. If a normal cab fare is ₹293.50, then 2.5 times the fare will be ____________.

Ria has to book a cab at 10 pm to go to her home from office. Because of the peak time the cab will charge 2.5 times that of normal. If without peak charges the fare from home to office is Rs.293.5, then what will be the total fare now?

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Ria booked a cab at 10 pm. Due to peak hours the cab charged 2.5 times the normal fare. If the normal fare is ₹293.50. Find her total fare.

The correct option is D ₹733.75 As the cab charges 2.5 times the normal fare, the original fare gets multiplied by the extra charges. So, 2.5×293.50=2510×293510=73375100=733.75. Now Ria has to pay ₹733.75 as the total fare.

The correct option is D
₹733.75

As the cab charges 2.5 times the normal fare, the original fare gets multiplied by the extra charges.

So, $2.5 \times 293.50 = \frac{25}{10} \times \frac{2935}{10} = \frac{73375}{100} = 733.75$ .

Now Ria has to pay ₹733.75 as the total fare.