Question

Rinku has built a cuboidal water tank in his house. The top of the water tank is covered with an iron lid. He wants to cover the inner surface of tank including the base with tiles of size $10cm\times 8cm$. If the dimensions of the water tank are $180cm\times 120cm\times 60cm$ and cost of tiles is $Rs.480$ per dozen, then find the total amount required for tiles.

Answer 1

Given tank is in cuboldal shape so Total inner surface area of water tank including the base without top.

$=2(l+b)\times h+l\times b$

$=2(180+120)\times 60+180\times 120$

$=36000+21600$

$=57600c{m}^2$

Given Area of each time tile $=10\times 8$

$=80c{m}^2$

$\therefore$ Number of tiles required $=\frac{57600}{80}$

$=720$

Given rate of tiles required us $Rs.720$ per dozen.

Total amount required for 720 tiles is $=\frac{480}{12}\times 720$

$=Rs.28800$