Question

Hameed has a built a cubical water tank with lid for house, with each outer edge $1.5m$ long. He gets the outer surface of the tank excluding the base, covered with square tiles of side $25cm$. Find how much he would spend for the tiles, if the cost of tiles is $Rs.360$ per dozen.

Answer 1

The length of the each side of water tank $=1.5m=150cm$

As it is given that base is not covered with tiles so, five sides of the tank are

covered with tiles.

Therefore,

Surface area of water tank $=5a^2=5(150{)}^2=112500c{m}^2$

Side of tile $=25cm$

Area of tile $={25}^2=625c{m}^2$

Number of tiles to cover five sides of the tank $=\frac{112500}{625}=180$

Now,

Cost of one dozen tiles $=Rs.360$

Hence, total cost of $180=\frac{360}{12}\times 180=Rs.5400$