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Byju's Answer
Standard XII
Physics
Ideal Gas Equation from KTG
RMS speed of ...
Question
RMS speed of molecules of gas A at temperature T1 is v and that of molecules of gas B at temperature T2 is 2v. Then which of the following is necessarily true? Options: 1)T2 = 2T1 2)T2 < T1 3)T2 > T1 4)None of these
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Q.
A box contains
N
molecules of a perfect ideal gas at temperature
T
1
and pressure
P
1
. The number of molecules in the box is doubled keeping the total kinetic energy of the gas same as before. If the new pressure is
P
2
and new temperature is
T
2
, then
Q.
A box contains
N
molecules of a perfect gas at temperature
T
1
and pressure
P
1
. The number of molecules in the box is doubled keeping the total kinetic energy of the gas same as before. If the new pressure and temperature are
P
2
are
T
2
respectively, then
Q.
N
1
molecules of a gas at temperature
T
1
are mixed with
N
2
molecules at temperature
T
2
. The resulting temperature of the mixture gas is
Q.
N
molecules of an ideal gas at temperature
T
1
and pressure
P
1
are contained in a closed box. The molecules in the box gets doubled, Keeping total kinetic energy same. If new pressure is
P
2
and temperature is
T
2
, Then:
Q.
Calculate the temperatures (
T
1
&
T
2
) (in
K
) at which the molecules of the first two members of the homologous series
C
n
H
2
n
+
2
will have the same
r
m
s
speed as
C
O
2
gas has 770
K
.
Then,
T
1
+
T
2
=
?
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