Question

Rohan purchased $4\frac{1}{2}kg$apples and $5\frac{3}{4}kg$oranges. What is the total weight of fruits purchased by him?

Answer 1

Find the total weight of fruits purchased by Rohan.

The weight of the apple purchased by Rohan $=4\frac{1}{2}kg=\frac{9}{2}kg$

and the weight of the orange purchased by Rohan $=5\frac{3}{4}kg=\frac{23}{4}kg$

The total weight of fruits purchased by Rohan $=Weightofapple+Weightoforange$

$$\begin{gathered} =\frac{9}{2}+\frac{23}{4} \\ =\frac{9\times 2}{2\times 2}+\frac{23}{4} \\ =\frac{18}{4}+\frac{23}{4} \\ =\frac{18+23}{4} \\ =\frac{41}{4} \\ =10\frac{1}{4} \end{gathered}$$

$\therefore$The total weight of fruits purchased by Rohan is $10\frac{1}{4}kg$