Question

Ron joins two ropes of length $4\frac{3}{8}m$ and $3\frac{1}{2}m$, and then cuts $\frac{21}{4}m$ of rope. What is the remaining length of the rope?

• A. $6m$
• B. $5\frac{5}{8}m$
• C. $5m$
• D. $\frac{5}{8}m$

Answer 1

The correct option is B $5\frac{5}{8}m$

Sum of $4\frac{3}{8}m$ and $3\frac{1}{2}m=4\frac{3}{8}+3\frac{1}{2}$
$=\frac{35}{8}+\frac{7}{2}=\frac{35}{8}+\frac{28}{8}=\frac{63}{8}=7\frac{7}{8}m$
Ron cut 214 m of rope from $7\frac{7}{8}m$
$=7\frac{7}{8}-2\frac{1}{4}=\frac{63}{8}-\frac{9}{4}=\frac{63}{8}-\frac{18}{8}=\frac{45}{8}=5\frac{5}{8}m$
Hence, Option A is correct.