Roots of quadratic equation $10 x^{2} + 3 x - 4 = 0$ are

\frac{- 1}{2}, \frac{- 4}{5}

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\frac{1}{2}, \frac{- 4}{5}

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\frac{1}{2}, \frac{4}{5}

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\frac{- 1}{2}, \frac{4}{5}

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Solution

The correct option is A $\frac{1}{2}, \frac{- 4}{5}$
Given equation is:
$10 x^{2} + 3 x - 4 = 0$
$10 x^{2} + 8 x - 5 x - 4 = 0$
$2 x (5 x + 4) - 1 (5 x + 4) = 0$
$(2 x - 1) (5 x + 4) = 0$
$∴ x = \frac{1}{2}, \frac{- 4}{5}$
$∴$ the roots of the given equation are $\frac{1}{2}, \frac{- 4}{5}$

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Similar questions

Q. Determine whether the values given against each of the quadratic equation are the roots of the equation.
(1) x² + 4x – 5 = 0 , x = 1, –1
(2) 2m² – 5m = 0,

m = 2, \frac{5}{2}

Determine the nature of the roots of the following quadratic equations:
$(i) 2 x^{2} - 3 x + 5 = 0 (i i) 3 x^{2} - 6 x + 3 = 0 (i i i) \frac{3}{5} x^{2} - \frac{2}{3} x + 1 = 0 (i v) 3 x^{2} - 4 \sqrt{3} x + 4 = 0 (v) 3 x^{2} - 2 \sqrt{6} x + 2 = 0$

Q. The roots of the quadratic equation

2 (3 x + 5) (2 x - 4) = 0

are

Find the roots of quadratic equation $x^{2} - 5 x + 4 = 0$ .

Find the roots of the $3 x^{2} - 5 x + 2 = 0$ quadratic equation, using the quadratic formula.

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Roots of quadratic equation 10x2+3x−4=0 are

The correct option is A 12,−45Given equation is:10x2+3x−4=010x2+8x−5x−4=02x(5x+4)−1(5x+4)=0(2x−1)(5x+4)=0∴x=12,−45∴ the roots of the given equation are 12,−45

Roots of quadratic equation $10 x^{2} + 3 x - 4 = 0$ are

The correct option is A $\frac{1}{2}, \frac{- 4}{5}$
Given equation is:
$10 x^{2} + 3 x - 4 = 0$
$10 x^{2} + 8 x - 5 x - 4 = 0$
$2 x (5 x + 4) - 1 (5 x + 4) = 0$
$(2 x - 1) (5 x + 4) = 0$
$∴ x = \frac{1}{2}, \frac{- 4}{5}$
$∴$ the roots of the given equation are $\frac{1}{2}, \frac{- 4}{5}$