Roots of quadratic equation $x^{2} - x - 132 = 0$ are

12, 11

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- 12, 11

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- 12, - 11

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12, - 11

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Solution

The correct option is C $12, - 11$
Given equation is

$x^{2} - x - 132 = 0$
$x^{2} - 12 x + 11 x - 132 = 0$
$(x - 12) (x + 11) = 0$
$∴ x = - 11, 12$
$∴$ roots of the given equation are $- 11, 12$

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