Roots of the quadratic equation $p^{2} - 12 p + 32 = 0$ are:

p = - 8, - 4

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p = 8, - 4

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p = 8, 4

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p = - 8, 4

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Solution

The correct option is C $p = 8, 4$
Given equation is
$p^{2} - 12 p + 32 = 0$
$p^{2} - 8 p - 4 p + 32 = 0$
$(p - 4) (p - 8) = 0$
$∴ p = 4, 8$
$∴$ the roots of the given equation are $4, 8$

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