$R s . 6050$ is borrowed at $6.5 %$ rate of interest p.a.. Find the interest and the amount to be paid at the end of $3$ years.

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Solution

interest= $\frac{p * r * t}{100}$
p = principal amount , r = rate , t = time
interest= $\frac{6050 * 6.5 * 3}{100}$
interest = RS. 1179.75
total amount = interest+ principal amount
= 6050+1179.75 = Rs 7229.75

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Rs.6050 is borrowed at 6.5% rate of interest p.a.. Find the interest and the amount to be paid at the end of 3 years.

interest=p∗r∗t100p = principal amount , r = rate , t = timeinterest=6050∗6.5∗3100interest = RS. 1179.75total amount = interest+ principal amount = 6050+1179.75 = Rs 7229.75

$R s . 6050$ is borrowed at $6.5 %$ rate of interest p.a.. Find the interest and the amount to be paid at the end of $3$ years.

interest= $\frac{p * r * t}{100}$
p = principal amount , r = rate , t = time
interest= $\frac{6050 * 6.5 * 3}{100}$
interest = RS. 1179.75
total amount = interest+ principal amount
= 6050+1179.75 = Rs 7229.75