S and T are 2 points on sides PR&QR of a PQR such that P = < RTS. Show that RPQ is similar to ?

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Solution

Given : $∠ P = ∠ R T S$
Also, $∠ S R T = ∠ P R Q$ (Common)
$∴$ By AA similarity criterion
$Δ R T S \approx Δ R P S$

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△ P Q R

∠ P = ∠ R T S

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S and T are point on sides PR and QR of ΔPQR such that ∠P = ∠RTS. Show that ΔRPQ ∼ ΔRTS.

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∠ P = ∠ R T S

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State True or False.
S and T are point on sides PR and QR of ∆PQR such that ∠P = ∠RTS.
Then, ∆RPQ ∼ ∆RTS.

In Fig. T is a point on side QR of △PQR and S is a point such that RT = ST. Prove that PQ + PR > QS

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