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Question

# S and T can do a piece of work in 40 days and 24 days respectively. S started the work alone and then after 5 days T joined him till the completion of the work. How long did the work last?

A

12.5 days

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B

18.675 days

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C

13.125 days

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D

20 days

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E

18.125 days

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Solution

## The correct option is E 18.125 days Work done by S in 5 days = (140 × 5) = 18, Remaining work = (1 − 18) = 78 (S + T)'s 1 day's work = (140 + 124) = 8120 = 115 Now, 115 work is done by S and T in 1 day. So, 78 work will be done by S and T in (15 × 78) \\ = 13.125 days Hence, total time taken = (13.125 + 5) days = 18.125 days

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