Question

s-character in hybrid orbitals of $C{H}_4$ and $BeC{l}_2$ are respectively:

• A. 0.75, 0.5
• B. 0.25, 0.5
• C. 0.75, 0.334
• D. 0.25, 0.33

Answer 1

The correct option is B 0.25, 0.5

s - character in hybrid orbitals of $C{H}_4$ and $BeC{l}_2$ are $0.25$ and $0.5$ respectively.
In $C{H}_4$, $C$ atom is $s{p}^3$ hybridised. So s-character is $\frac{1}{4}=0.25$.
In $BeC{l}_2$, the $Be$ atom is $sp$ hybridised. So $s-$character is $\frac{1}{2}=0.5$.