$S_{N^{1}}$ reactivity of the following halides,
(i) $(C H_{3})_{3} C B r$
(ii) $(C_{6} H_{5})_{2} C H B r$
(iii) $(C_{6} H_{5})_{2} C (C H_{3}) B r$
(iv) $(C H_{3})_{2} C H B r$
will be in the order:

i v > i > i i > i i i

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i i > i > i i i > i v

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i > i i i > i i > i v

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i i i > i i > i > i v

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Solution

The correct option is C $i i i > i i > i > i v$
The more stable the cation the more reactive they are ${S N}^{1}$ .
As ${(C_{6} H_{5})}_{2} (+) C ({C H}_{5})$ is more stable due to two Aryl group and an Alkyl group.
$\Rightarrow$ iii > ii > i > iv

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Similar questions

S_{N} 1

(C H_{3})_{3} C B r

(C_{6} H_{5})_{2} C H B r

(C_{6} H_{5})_{2} C (C H_{3}) B r

(C H_{3})_{2} C H B r

C_{2} H_{5} B r

50^{\circ}

Predict the order of reactivity of the following compounds in dehydrohalogenation.

i . {(C H_{3})}_{3} C - C H_{2} B r

i i . C l C H_{2} C H = C H_{2}

i i i . C l C H_{2} C H_{2} C H_{3}

i v . B r C H_{2} C H_{2} C H_{3}

In the following molecules:
$C H_{3} B r, C H_{3} F, C H_{3} C l, C H_{3} I I, I I, I I I, I V$
The correct order of dipole moment will be:

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