$S O_{2}$ turns acidified $K_{2} {C r}_{2} O_{7}$ green.

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Solution

Sulfur dioxide gas turns acidified potassium dichromate ( $V I$ ) solution from orange to green. Chromium is reduced from ( $V I$ ) to ( $I I I$ ) after reaction.
$K_{2} {C r}_{2} O_{7} + 3 {S O}_{2} + H_{2} {S O}_{4} ⟶ {C r}_{2} {({S O}_{4})}_{3} + K_{2} {S O}_{4} + H_{2} O$
Hence, true.

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