The correct option is A 815.5 g
Let the amount of BaSO4 precipitate obtained be ′a′ g.
Since the atoms of S are conserved,
Applying POAC on sulphur,
1×moles of S=1×moles of BaSO4
⇒1×weight of sulphurmolar mass=1×weight of BaSO4molar mass of BaSO4
⇒1×11232=1×a233
On solving, a=815.5 g
Therefore, the precipitate of barium sulphate obtained is 815.5 g.