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Standard X

Mathematics

Formula for Sum of n Terms of an AP

S, T and U ca...

Question

S, T and U can complete work in $40$ , $48$ and $60$ days respectively. They received Rs. $10800$ to complete the work. They begin the work together but T left $2$ days before the completion of the work and U left $5$ days before the completion of the work. S has completed the remaining work alone. What is the share of S(in Rs.) from total money?

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Solution

$S = 40 \times 6 = 240$

$T = 48 \times 5 = 240$

$U = 60 \times 4 = 240$

Consider x days as time taken to complete the work.

$6 x + 5 (x - 2) + 4 (x - 5) = 240$

$15 x = 270$

$∴ x = 18$

work done by S $= 6 \times 18 = 108$

Therefore share of S $= \frac{108}{240} \times 10800 = R s .4860$

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S=40×6=240T=48×5=240U=60×4=240Consider x days as time taken to complete the work.6x+5(x−2)+4(x−5)=24015x=270∴x=18work done by S=6×18=108Therefore share of S=108240×10800=Rs.4860

$S = 40 \times 6 = 240$

$T = 48 \times 5 = 240$

$U = 60 \times 4 = 240$

Consider x days as time taken to complete the work.

$6 x + 5 (x - 2) + 4 (x - 5) = 240$

$15 x = 270$

$∴ x = 18$

work done by S $= 6 \times 18 = 108$

Therefore share of S $= \frac{108}{240} \times 10800 = R s .4860$