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Zinc Ion

Salt A makes ...

Question

Salt (A) makes part of electrode and is insoluble in water. (A) is blackened by ${N H}_{3}$ forming (B). (B) is soluble in aqua regia forming (C). (C) gives orange precipitate with KI but the precipitate dissolves in excess of KI forming (D). Here,
(A) : ${H g}_{2} {C l}_{2}$ (calomel)
(B) : $({H g N H}_{2} C l + H g)$
(C) : ${H g C l}_{2}$
(D) : $K_{2} {H g I}_{4}$
If true enter 1, else enter 0.

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Solution

The salt (A) is ${H g}_{2} {C l}_{2}$ . It is a part of calomel electrode. It is water insoluble.
It reacts with ammonia to form (B) which is $({H g N H}_{2} C l + H g)$ . It is black in colour.
$H g_{2} C l_{2} + 2 N H_{4} O H \to H_{2} N - H g - C l + H g ↓ b l a c k + N H_{4} C l + 2 H_{2} O$
(B) dissolves in aqua regia to form (C) which is ${H g C l}_{2}$ .
(C) gives orange precipitate with KI which dissolves in excess of KI to form (D) which is $K_{2} {H g I}_{4}$ .
$H g C l_{2} + 2 K I \to H g I_{2} ↓ o r a n g e p r e c i p i t a t e + 2 K C l$
$H g I_{2} + 2 K I (e x c e s s) \to K_{2} [H g I_{4}]$

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