Same current is being passed through a copper voltameter and silver voltameter. The rate of increase in weight of the cathodes in the two voltameters will be proportional to

relative densities

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atomic masses

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atomic numbers

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none of the above

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Solution

The correct option is C $none of the above$
According to Faraday's law of electrolysis, the amount of substance deposited $m = z I t$
where $z =$ electrochemical equivalent of substance,
$I =$ current $t$ is the time.
Thus, rate of increases of weight $(m / t)$ is proportional to $z$ and $I$ .

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Same current is being passed through a copper voltameter and silver voltameter. The rate of increase in weight of the cathodes in the two voltameters will be proportional to

The correct option is C none of the aboveAccording to Faraday's law of electrolysis, the amount of substance deposited m=zItwhere z= electrochemical equivalent of substance,I= current t is the time.Thus, rate of increases of weight (m/t) is proportional to z and I.

The correct option is C $none of the above$
According to Faraday's law of electrolysis, the amount of substance deposited $m = z I t$
where $z =$ electrochemical equivalent of substance,
$I =$ current $t$ is the time.
Thus, rate of increases of weight $(m / t)$ is proportional to $z$ and $I$ .