Same force acts on two bodies of different masses 3kg and 5kg initially at rest. The ratio of time required to acquire same ﬁnal velocity is:

5 : 3

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25 : 9

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9 : 25

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3 : 5

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Solution

The correct options are
B
25 : 9

D
3 : 5

$\begin{matrix} F = 3 a & F = 5 A a_{1} = \frac{F}{3} & a_{2} = \frac{F}{3} u_{1} = 0 & u_{2} = 0 v_{1} u_{1} = a_{1} t_{1} & v_{2} - u_{2} = a_{2} t_{2} v_{1} = \frac{F}{3} t_{1} & v_{2} = \frac{F}{3} t_{2} \end{matrix}$

$v_{1} = v_{2}$ they acquire equal velocity

$\frac{F}{3} t_{1} = \frac{F}{3} t_{2}$ $\frac{t_{1}}{t_{2}} = \frac{3}{5}$

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Same force acts on two bodies of different masses 3kg and 5kg initially at rest. The ratio of time required to acquire same ﬁnal velocity is:

The correct options are B 25 : 9 D 3 : 5 F=3aF=5Aa1=F3a2=F3u1=0u2=0v1u1=a1t1v2−u2=a2t2v1=F3t1v2=F3t2 v1=v2 they acquire equal velocity F3t1=F3t2 t1t2=35