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Standard VII

Mathematics

Area of Circle

Samuel wanted...

Question

Samuel wanted to implant some vertical stones along the boundary of his plot at a distance of $10$ m each. If length of the plot is $30$ m and the breadth is $15$ m, then the number of stones used is:

450

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45

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9

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10

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Solution

The correct option is D $9$
Perimeter of plot $= 2 (l + b) = 2 (30 + 15) = 90 m$
Distance between two stones $= 10 m$
Therefore, number of stones $= \frac{90}{10} = 9$

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Samuel wanted to implant some vertical stones along the boundary of his plot at a distance of 10 m each. If length of the plot is 30 m and the breadth is 15 m, then the number of stones used is:

The correct option is D 9Perimeter of plot=2(l+b)=2(30+15)=90mDistance between two stones=10mTherefore, number of stones=9010=9

Samuel wanted to implant some vertical stones along the boundary of his plot at a distance of $10$ m each. If length of the plot is $30$ m and the breadth is $15$ m, then the number of stones used is:

The correct option is D $9$
Perimeter of plot $= 2 (l + b) = 2 (30 + 15) = 90 m$
Distance between two stones $= 10 m$
Therefore, number of stones $= \frac{90}{10} = 9$