Sangeeta invested rupees 16500 partly in 10% Rupees 100 share at rupees 130 and partly in 8% Rs 100 shares at Rs 120if her total annual income from this share is RS 1180 find her investment in each case

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Solution

Let x is the amount invested in first case than amount invested in second case equal to 16500-x

First case

10% Rs 100 share at Rs 130

It means 10100/100 = 10 rupee he will get on investment of 130 rupee

So total amount he will get in this investment = (x/130)10 = x/13

Second case

8% Rs 100 share at 120

It means 8100/100 = 8 rupee he will get on investment of 120

(16500-x)8/120 = 1/15(16500-x)

Total annual income from shares = x/13 + (16500-x)/15

1180 = x/13 + (16500-x)/15

11801513 = 15x + (16500-x)13

230100 = 15x + 214500-13x

15600 = 2x

x = 15600/2

x = 7800

So amount invested in first case = 7800 and in second case = 16500-7800 = 8700

Answer :

First case = 7800

Second case = 8700

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