Santosh has $x$ pens, and $y$ pencils. Anjan has 3 pens less than Santosh and thrice the number of pencils. The expression for the total number of pens and pencils with Anjan is:

6x+3y - 3

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x+4y - 3

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x+3y - 2

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x+3y - 3

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Solution

The correct option is D
x+3y - 3

Anjan has $3$ pens less than Santosh.
$\Rightarrow$ Anjan has $(x - 3)$ pens.

Also, Anjan has is thrice the number of pencils
$\Rightarrow$ Anjan has $3 y$ pencils.

Total number of pens and pencils with Anjan is, $x - 3 + 3 y \Rightarrow x + 3 y - 3.$

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Santosh has x pens, and y pencils. Anjan has 3 pens less than Santosh and thrice the number of pencils. The expression for the total number of pens and pencils with Anjan is:

The correct option is D x+3y - 3 Anjan has 3 pens less than Santosh. ⇒ Anjan has (x−3) pens. Also, Anjan has is thrice the number of pencils ⇒ Anjan has 3y pencils. Total number of pens and pencils with Anjan is, x−3+3y⇒x+3y−3.

Santosh has $x$ pens, and $y$ pencils. Anjan has 3 pens less than Santosh and thrice the number of pencils. The expression for the total number of pens and pencils with Anjan is:

The correct option is D
x+3y - 3

Anjan has $3$ pens less than Santosh.
$\Rightarrow$ Anjan has $(x - 3)$ pens.

Also, Anjan has is thrice the number of pencils
$\Rightarrow$ Anjan has $3 y$ pencils.

Total number of pens and pencils with Anjan is, $x - 3 + 3 y \Rightarrow x + 3 y - 3.$