Question

Sanya, Aarushi, Manav and Kabir made greeting cards. Complete the table for their cards:

Answer 1

whose card Length width perimeter Areas

sanya 10 cm 8 cm 36 cm 80 sq.cm

Manav 11 cm 11 cm 44 cm 121 sq.cm

Aarushi 10 cm 8 cm 36 cm 80 sq.cm

Kabir 10 cm 10 cm 40 cm 100 sq.cm

sanya

we have length = 10 cm and width = 8 cm

perimeter =2(2+b)

= 2(10+8) = 2(18)

= 36 cm

Length of Manav's card =11 cm

Perimeter of his card =44 cm

Perimeter of card = sum of all its sides

=11+11+sum of other 2 sides

= 22+sum of other 2 sides

Now, sum of other two sides, 44-22=22 cm

so, width of manav's card =22/2, 11 cm

width of Arushi's card = 8 cm Area of card

$=8\times 10=80c{m}^2$

Now, we have to find length

Area of the card =80 cm

Length of Arushi's card = 80/8=10 cm.