Saponification (basic hydrolysis) $C_{6} H_{5} O | | C O C H_{3}$ will yeild :

C_{6} H_{5} - O | | C - O^{-} + H O - C H_{2} - C H_{3}

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C_{6} H_{5} - O | | C - O^{-} + H O C H_{3}

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C_{6} H_{5} C | | O O^{-} + H O^{-}

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C_{6} H_{5} C | | O O^{-} + H O C (C H_{3})_{3}

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Solution

The correct option is D $C_{6} H_{5} - O | | C - O^{-} + H O C H_{3}$
Saponification (basic hydrolysis) $C_{6} H_{5} - C (= O) - O C H_{3}$ . On basic hydrolysis reaction is only with $O H^{⊖}$ ion along with $H_{2} O$ . This reaction gives carboxylic acid and alcohol.
Option :B

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