Question

$\int \left({\sec }^{2}x+{\mathrm{cosec}}^{2}x\right)dx$

Answer 1

$$\begin{gathered} \int \left({\sec }^{2}x+{\mathrm{cosec}}^{2}x\right)dx \\ =\int {\sec }^{2}xdx+\int {\mathrm{cosec}}^{2}xdx \\ =\tan x-\cot x+\mathrm{C} \end{gathered}$$