Question

See the figure -1 :
The valves of $X$ and $Y$ are opened simultaneously.The white fumes of $N{H}_{4}Cl$ will first form at :

• A. $A$
• B. $B$
• C. $C$
• D. $A,B$ and $C$ simultaneously

Answer 1

Answer: (C)

$C$

According to Graham's law

Rate of Diffusion $\alpha \frac{1}{\sqrt{Molecularweight}}$

In both the gases $HCl$ is heavier than $N{H}_3$ and will diffuse less distance than $N{H}_3$. Thus $N{H}_{4}Cl$ will first form near $HCl$ and far from $N{H}_3$ because in same time $N{H}_3$ will diffuse double distance than $HCl$,