You visited us 1 times! Enjoying our articles? Unlock Full Access!

Hydrochloric Acid

Select a corr...

Question

Select a correct alternate.
$C a C O_{3} + 2 H C l ⟶ C a C l_{2} + H_{2} O + C O_{2}$
The volume of $H C l$ required to decompose $10$ g of $50 %$ pure $C a C O_{3}$ is :

1825

No worries! We‘ve got your back. Try BYJU‘S free classes today!

365

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9125

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2240

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $2240$ mL
The balanced reaction is as follows:
$C a C O_{3} + 2 H C l ⟶ C a C l_{2} + H_{2} O + C O_{2}$
$10$ g of $50 %$ pure means $5$ g $= \frac{5}{100} = 0.05$ mol
So, volume of $H C l$ required $= 2 \times 22400 \times 0.05 = 2240$ mL

Suggest Corrections

Similar questions

H C l

C a C O_{3}

H C l

C a C O_{3} + 2 H C l \to C a C l_{2} + C O_{2} + H_{2} O

C a C O_{3} + H C l \to C a C l_{2} + C O_{2} + H_{2} O

C a C O_{3}

25

0.75 M

H C l

C a C O_{2}

C a C O_{3} + 2 H C l \to C a C l_{2} + H_{2} O + C O_{2}

C a C l_{2}

C O_{2}

C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)

C a C O_{3}

10

C a C O_{3}

250

1

2

Join BYJU'S Learning Program