Question

Select correct statements regarding $B{F}_{2}N{H}_2$ molecule:

• A. $F-\hat{B}-F$ bond angle $<{120}^o$
• B. $H-\hat{N}-H$ bond angle $>{109}^o{28}^o$
• C. $H-\hat{N}-H$ bond angle$<{109}^{o}28$
• D. $F-\hat{B}-F$ bond angle $>{120}^o$

Answer 1

The correct option is A $F-\hat{B}-F$ bond angle $<{120}^o$

Boron has vacant orbitals and nitrogen has a lone pair of electrons. Hence nitrogen donates the lone pair to Boron. So the bond angle between $F-\hat{B}-F$ reduces from ${120}^o$

So $F-B_F$ bondangle $<{120}^o$