Select the basic strength order of following molecules.

I I I > I I > I

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I I > I I I > I

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I > I I I > I I

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I I I > I > I I

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Solution

The correct option is A $I I I > I I > I$
Since in (III) lone pair is only involved in delocalisation, in (II) nitrogen is attached to the carbonyl (withdrawing group) and one alkyne group (donating group+I effect) which have the more basic character them the (I) in which (N) is attached to the two group i.e benzene and carbonyl.

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Similar questions

I . T l_{2} O

I I . A l_{2} O_{3}

I I I . T l_{2} O_{3}

I V . G a_{2} O_{3}

H_{2} C ¯ C H_{2}

H_{2} C = ¯ C H

C H \equiv ¯ C

- I

I . - C H_{2} N H_{2} I I . - C H = N H I I I . - C N

In the following molecules:
$B F_{3}, B C l_{3}, B B r_{3}, B I_{3} I, I I, I I I, I V$
The correct order of Lewis acidic strength will be:

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