Question

Select the correct I.U.P.A.C name for $\left[Cu{\left(N{H}_3\right)}_4\right]$ $\left[PtC{l}_4\right]$ :

• A. Tetraamminecopper (II) tetrachloridoplatinum (II)
• B. Tetraamminecopper (II) tetrachloridoplatinum (IV)
• C. Tetraamminecopper(II) tetrachloridoplatinate (II)
• D. Tetraamminecuprate(II) tetrachloridoplatinate (II)

Answer 1

The correct option is C Tetraamminecopper(II) tetrachloridoplatinate (II)

Option (C) is correct. I.U.P.A.C name for $\left[Cu{\left(N{H}_3\right)}_4\right]$ $\left[PtC{l}_4\right]$ complex is tetraamminecopper(II) tetrachloridoplatinate (II).

$N{H}_3$ is neutral, making the first complex positively charged overall, so cobalt is in +2 oxidation state. $Cl$ has a -1 charge, making the second complex the anion. As the charge on platinum is -2 so the name ends with -ate followed by the charge in roman letters.