66
Question
Select the correct order of bond angle.
Select the correct order of bond angle.
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Solution
The correct options are
A Br−^P−Br(OPBr3)>Cl−^P−F(OPCl3)>F−^P−F(OPF3)
B H−^C−H(CH4)>H−^N−H(NH3)
(A) The correct order of bond angles is
Br−^P−Br(OPBr3)>Cl−^P−F(OPCl3)>F−^P−F(OPF3)
With increase in the electronegativity of halogens, the electrons of P-X bonds are attracted more towards halogen.
Thus, the repulsion between the bond pair of electrons of P-X bond decreases.
This decreases, the X−P−X bond angle.
Thus, the option A is correct.
(B) The correct order of bond angles is
H−^C−H(CH4)>H−^N−H(NH3)
Since, N is more electronegative than C, it attracts th bond pair of electrons towards itself. Hence, the lone pair - bond pair repulsion in ammonia increases and the bond angle decreases.
In methane only bond pair bond pair repulsion is present.
Bond-pair bond pair repulsion is lower than lone pair - bond pair repulsion.
Thus, the option A is correct.
(C) The correct order of bond angles is
H−^C−H(CH4)>H−^N−H(NH3)
Since, N is more electronegative than C, it attracts th bond pair of electrons towards itself. Hence, the lone pair - bond pair repulsion in ammonia increases and the bond angle decreases.
In methane only bond pair bond pair repulsion is present.
Bond-pair bond pair repulsion is lower than lone pair - bond pair repulsion.
Thus, the option C is incorrect.
(D) The correct order of bond angles is
Br−^P−Br(OPBr3)>Cl−^P−F(OPCl3)>F−^P−F(OPF3)
With increase in the electronegativity of halogens, the electrons of P−X bonds are attracted more towards halogen.
Thus, the repulsion between the bond pair of electrons of P−X bond decreases.
This decreases, the X−P−X bond angle.
Thus, the option D is incorrect.
A Br−^P−Br(OPBr3)>Cl−^P−F(OPCl3)>F−^P−F(OPF3)
B H−^C−H(CH4)>H−^N−H(NH3)
(A) The correct order of bond angles is
Br−^P−Br(OPBr3)>Cl−^P−F(OPCl3)>F−^P−F(OPF3)
With increase in the electronegativity of halogens, the electrons of P-X bonds are attracted more towards halogen.
Thus, the repulsion between the bond pair of electrons of P-X bond decreases.
This decreases, the X−P−X bond angle.
Thus, the option A is correct.
(B) The correct order of bond angles is
H−^C−H(CH4)>H−^N−H(NH3)
Since, N is more electronegative than C, it attracts th bond pair of electrons towards itself. Hence, the lone pair - bond pair repulsion in ammonia increases and the bond angle decreases.
In methane only bond pair bond pair repulsion is present.
Bond-pair bond pair repulsion is lower than lone pair - bond pair repulsion.
Thus, the option A is correct.
(C) The correct order of bond angles is
H−^C−H(CH4)>H−^N−H(NH3)
Since, N is more electronegative than C, it attracts th bond pair of electrons towards itself. Hence, the lone pair - bond pair repulsion in ammonia increases and the bond angle decreases.
In methane only bond pair bond pair repulsion is present.
Bond-pair bond pair repulsion is lower than lone pair - bond pair repulsion.
Thus, the option C is incorrect.
(D) The correct order of bond angles is
Br−^P−Br(OPBr3)>Cl−^P−F(OPCl3)>F−^P−F(OPF3)
With increase in the electronegativity of halogens, the electrons of P−X bonds are attracted more towards halogen.
Thus, the repulsion between the bond pair of electrons of P−X bond decreases.
This decreases, the X−P−X bond angle.
Thus, the option D is incorrect.
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