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Question

Select the correct properties for the following molecules :
(I) CH2F2
(II) CHF3
(III) CH3F

A
CF bond length order : CH3F>CH2F2>CHF3
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B
CH bond length order : CH3F>CH2F2>CHF3
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C
Shape is not perfect tetrahedral for given compounds.
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D
Dipole moment is non-zero for given compounds.
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Solution

The correct options are
A CF bond length order : CH3F>CH2F2>CHF3
B CH bond length order : CH3F>CH2F2>CHF3
C Shape is not perfect tetrahedral for given compounds.
D Dipole moment is non-zero for given compounds.
All the four statements are correct.
(A) The CF bond length decreases in the order : CH3F>CH2F2>CHF3
As the number of F atoms increases, the partial positive charge on the C atom increases.
Hence, it more strongly attracts the bond pair of electrons.
Hence, the bond strength increases and the bond length decreases.
(B) The CH bond length decreases in the order : CH3F>CH2F2>CHF3
As the number of F atoms increases, the partial positive charge on the C atom increases.
Hence, it more strongly attracts the bond pair of electrons.
Hence, the bond strength increases and the bond length decreases.
(C) Shape is not perfect tetrahedral for given compounds.
This is because all the four atoms attached to central carbon atom are not same.
Hence, the bond lengths and bond angles are different.
(D) Dipole moment is non-zero for given compounds.
As the individual bond dipoles do not cancel each other.

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