Question

Select the correct statement (s) about the compound $NO\left[B{F}_4\right]$

• A. It has 5$\sigma$ and 2$\pi$ bond
• B. Nitrogen - oxygen bond length is higher than nitric oxide $\left(NO\right)$
• C. It is a diamagnetic species
• D. $BF$ bond length in this compound is lower than in $B{F}_3$

Answer 1

Answer: (A), (C)

The correct options are
A It has 5$\sigma$ and 2$\pi$ bond
C It is a diamagnetic species

$NO\left[B{F}_4\right]$ can be separated into $N{O}^{+}$ and $B{F}_4^{-}$.
$B{F}_4^{-}$ has $4$ bonds, as single bonds between $B$ and $F$.
$N{O}^{+}$ has $1$ bonds, $2$ bonds.
It is a diamagnetic species.