The correct options are
A Magnetic moment of the species is zero
B B−F bond energy is lower in this compound than in
BF3 C It has
5σ and
2π bond
D Nitrogen oxygen bond order is same as in
N2NO+[BF4]− No. of
σ bonds in
[BF4]−=4 B. O. of
NO+=3.0, i.e. one sigma bond and two
π bonds.
∴ It has 5 sigma and two
π bonds.
MOT of
NO+ is
Electronic configuration of
NO+ is:
σ(1s)2σ∗(1s)2σ(2s)2σ∗(2s)2σ(2pz)2π(2px)2π(2py)2 Bond Order of
NO+=(Nb−Na)2=(10−4)2=3 Bond Order of
N2 is also 3. So, the bond order of
NO+ is equal to bond order of
N2.
NO+ has no unpaired electron. So it is diamagnetic.
[BF4]− has no unpaired electron. So, it is also diamagnetic.
Hence the magnetic moment of
[NO][BF4] is zero and is diamagnetic.
B−F bond energy is lower in
BF−4 than in
BF3, due to presence of back bonding in
BF3.