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Bond Order by MOT

What is the b...

Question

What is the bond order of underlined species in $N O^{+} [B F_{4}]^{-}$ ?

1.3

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Solution

The correct option is D $3$
Given species $- N O^{+} B F_{4}^{-}$
Bond Order of ${N O}^{+}$ is 3, this is because bond order is 3 for $14 e^{-} s .$

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Similar questions

N O H S O_{4}

N O [B F_{4}]

O - N - O

{N O}_{2}, {N O}_{2}^{+}

{N O}_{2}^{-}

N O

2.5

{N O}^{+}

3

The species having bond order different from that in CO is

1)NO-

2)NO+

3)CN-

4)N²

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