Question

Select the correct statements for the case when $C{l}_2$ gas reacts with hot and concentrated sodium hydroxide solution.

• A. The oxidation number of $C{l}_2$ changes from zero to -1.
• B. The oxidation number of $C{l}_2$ changes from zero to +5.
• C. The oxidation number of $C{l}_2$ changes from zero to +3.
• D. The oxidation number of $C{l}_2$ changes from zero to -3.

Answer 1

Answer: (A), (B)

The correct options are
A The oxidation number of $C{l}_2$ changes from zero to -1.
B The oxidation number of $C{l}_2$ changes from zero to +5.

The reaction is given below:
$6NaOH+3C{l}_2\to 5NaCl+NaCl{O}_3+3H_{2}O$
0 -1 +5
reduction oxidation
Hence, the oxidation state of $C{l}_2$ changes from $0$ to $-1$ and from $0$ to $+5$.