Select the diamagnetic complex ion amongst the following complexes.
(Atomic No. $F e = 26, C o = 27$ )

K_{3} [F e (N H_{3})_{6}]

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[C o (N H_{3})_{6}] C l_{3}

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K_{3} [F e F_{6}]

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K_{3} [C o F_{6}]

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Solution

The correct option is C $[C o (N H_{3})_{6}] C l_{3}$
Since $N H_{3}$ is strong field ligand hence $d^{6}$ exists as $t_{2 g}^{6} e_{g}^{0}$ where all $e^{-}$ are paired. Therefore it is diamagnetic.

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F e = 26, C o = 27

K_{3} [F e (C N_{6}] - K

[C o (N H_{3})_{6}] C l_{3} - L

N a_{3} [C o (o x a l a t e)_{3}] - M

[N i (H_{2} O)_{6}] C l_{2} - N

K_{2} [P t (C N)_{4}] - O

[Z n (H_{2} O)_{6}] (N O_{3})_{2} - P

K_{3} [F e (C N)_{6}

[C o (N H_{3})_{6}] C l_{3}

(K - P) K_{3} [F e (C N)_{6} (K), [C o (N H_{3})_{6}] C l_{3} (L), N a_{3} [C o (o x a l a t e)_{3}] (M), [N i (H_{2} O)_{6}] C l_{2} (N), K_{2} [P t (C N)_{4}] (O) and [Z n (H_{2} O)_{6}] (N O_{3})_{2} (P)

d^{2} s p^{3}

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