Question

Select the option that correctly fills the blanks in the following statements.
A. Glucose has (i) carbon atoms, pyruvic acid has (ii) carbon atoms and the acetyl group has (iii) carbon atoms.
B. Electrons enter the electron transport system as parts of hydrogen atoms attached to (i) and (ii).

• A. A-(i)-6,(ii)-4,(iii)-3 ; B -(i)-NADH , (ii)- $FAD{H}_2$
• B. A-(i)-6,(ii)-3,(iii)-2 ; B- (i)-NADH , (ii)- $FAD{H}_2$
• C. A-(i)-6,(ii)-3,(iii)-2 ; B-ATP , (ii)- GTP
• D. A-(i)-6,(ii)-4,(iii)-3 ; B-ATP , (ii)- GTP

Answer 1

Answer: (B)

A-(i)-6,(ii)-3,(iii)-2 ; B- (i)-NADH , (ii)- $FAD{H}_2$

A. i- Glucose molecule has 6 carbon atoms. It is a monosaccharide It is produced during the Calvin cycle.

ii. Pyruvic acid has 3 carbon atoms. It produces during the glycolytic breakdown of glucose into 2 pyruvic acids.

iii Pyruvic acid generated in the glycolysis enters in the mitochondrial matrix, undergoes oxidative decarboxylation and forms 2 carbon acetyl Co=A which enters in Kreb's cycle.

B. The metabolic pathway through which the electron passes from one carrier to another is called an electron transport system. The steps in the respiratory process are to release and utilise the energy stored in NADH + H${}^{+}$ and FADH${}_2$.

So, the correct answer is 'A-(i)-6, (ii)-3, (iii)-2; B-(i)-NADH, (ii)- FADH${}_2$'.