Question

Seven resistors are connected as shown in the diagram.


The equivalent resistance in $\text{ohms}$ of this network between $A$ and $B$ is:

• A. $6$
• B. $8$
• C. $12$
• D. $20$

Answer 1

The correct option is A $6$

As $8\Omega ||10\Omega$ and $30\Omega ||6\Omega$. The given circuit is equivalent to


As $\frac{10}{5}=\frac{8}{4}$, so this is balanced Wheatstone network.
Therefore, $R=\frac{(5+4)\times (10+8)}{9+18}=6\text{ohm}$